Given (5x – 1)/3 – (2x – 2)/3 = 1
(5x – 1 – 2x – 2)/3 = 1
(3x + 1)/3 = 1
Multiplying both sides by 3 we get
(3x + 1)/3 × 3 = 1 × 3
(3x + 1) = 3
Subtracting 1 from both sides we get
3x + 1 – 1 = 3 – 1
3x = 2
Dividing both sides by 3, we get
3x + 1 – 1 = 3 -1
3x = 2
Dividing both sides by 3, we get
3x/3 = 2/3
x = 2/3
Verification:
Substituting x = 2/3 in LHS, we get
(5 (2/3) – 1)/3 – (2 (2/3) – 2)/3 = 1
(10/3 -1)/3 – (4/3 – 2)/3 = 1
(7/3)/3 – (-2/3)/3 = 1
(7/9) + (2/9) = 1
(9/9) = 1
1 = 1
Thus LHS = RHS
Hence, verified.