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In an examination, 92% of the candidates passed and 46 failed. How many candidates appeared?

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Let the total number of candidates be x

Number of candidates who failed = 46

Number of candidates who passed = 92% of x

According to the given condition

92% of x = x – 46

 ⇒ (92/100) x = x – 6

 ⇒ 92x = 100x – 4600

 ⇒ -8x = – 4600

 ⇒ x = 4600/8 = 575

Number of candidates who appeared for the examination = 575

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