Given Principal amount P = Rs 60000
Time period T = 2 years
Rate of interest R = 10% p.a.
We know that simple interest = (P × T × R)/100
On substituting these values in above equation we get
SI = (60000 × 2 × 10)/100
= Rs 12000
Principal amount P = Rs 60000
Time period T = 2 years
Rate of interest R = 9% p.a.
We know that simple interest = (P × T × R)/100
On substituting these values in above equation we get
SI = (60000 × 2 × 9)/100
= Rs 10800
Amount gained by Rohit = Rs 12000 − Rs 10800
= Rs 1200