$$\begin{array}{1}{a_(1)}=\dfrac {{{a_{3 }}-{a_{2))}}{2).....\left(i \right) W \Rightarrow {a_{2}}-{a_{3}}+2{a_{1} }=0..\left(i \right) 2T-(M_(1))g-(M_(1 }}{a_(1)} \\ \Rightarrow 2Tg={a_{1} left( ( ii) \right) \I Right arrow T-28=2{ a_{2}).\left( (ii) \right) \\\Rightarrow 3g-T=3{a_{3} ..... \left({iv} \right) \Rightarrow (a_(1))-\dfrac ((19g)(2g) }\\{a_{2}}=\dfrac{{-\pi g)}{{2g}} {{{ a_{3} }=\frac 21g)){(2g)) \end{array}$$
