Given ∠1 and ∠2 are in the ratio 3: 2
Let us take the angles as 3x, 2x
∠1 and ∠2 are linear pair [from the figure]
3x + 2x = 180°
5x = 180°
x = 180°/5
x = 36°
Therefore, ∠1 = 3x = 3(36) = 108°
∠2 = 2x = 2(36) = 72°
∠1 and ∠5 are corresponding angles
Therefore ∠1 = ∠5
Hence, ∠5 = 108°
∠2 and ∠6 are corresponding angles
So ∠2 = ∠6
Therefore, ∠6 = 72°
∠4 and ∠6 are alternate pair of angles
∠4 = ∠6 = 72°
Therefore, ∠4 = 72°
∠3 and ∠5 are alternate pair of angles
∠3 = ∠5 = 108°
Therefore, ∠5 = 108°
∠2 and ∠8 are alternate exterior of angles
∠2 = ∠8 = 72°
Therefore, ∠8 = 72°
∠1 and ∠7 are alternate exterior of angles
∠1 = ∠7 = 108°
Therefore, ∠7 = 108°
Hence, ∠1 = 108°, ∠2 = 72°, ∠3 = 108°, ∠4 = 72°, ∠5 = 108°, ∠6 = 72°, ∠7 = 108°, ∠8 = 72°