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In Fig., if AB ∥ CD and CD ∥ EF, find ∠ACE

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In Fig., if AB ∥ CD and CD ∥ EF, find ∠ACE

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Given that, AB ∥ CD and CD ∥ EF

Sum of the interior angles,

∠CEF + ∠ECD = 180°

130° + ∠ECD = 180°

∠ECD = 180° – 130°

∠ECD = 50°

We know that alternate angles are equal

∠BAC = ∠ACD

∠BAC = ∠ECD + ∠ACE

∠ACE = 70° – 50°

∠ACE = 20°

Therefore, ∠ACE = 20°

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