Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
978 views
in Triangles by (56.3k points)

Two angles of a triangle are equal and the third angle is greater than each of those angles by 30°. Determine all the angles of the triangle.

1 Answer

+1 vote
by (30.5k points)
selected by
 
Best answer

Given that two angles of a triangle are equal

Let the first and second angle be x

Also given that third angle is greater than each of those angles by 30°

Therefore the third angle is greater than the first and second by 30° = x + 30°

The first and the second angles are equal

We know that sum of all the angles of a triangle = 180°

x + x + x + 30° = 180°

3x + 30 = 180

3x = 180 – 30

3x = 150

x = 150/3

x = 50°

Third angle = x + 30° = 50° + 30° = 80°

The first and the second angle is 50° and the third angle is 80°.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...