(a) x – 1 = 0
The given equation = x – 1 = 0
Add 1 to both the sides
Checking
x – 1 = 0
put the value of x = 1
1 – 1 = 0
∴ LHS = RHS (checked)
(b) x + 1 = 0
The given equation = x + 1 = 0
Subtract 1 from both the sides
x - 1 + 1 = 0 - 1
x = - 1
Verification
x+ 1 = 0
substitute the value of x = -1 then x + 1 = 0
(-1) + 1 = 0
0 = 0
LHS = RHS (verified)
(c) x – 1 = 5
The given equation is x – 1 = 5
Add 1 to both sides
x - 1 + 1 = 5 + 1
x = 6
Substitute the value in the equation x = 6.
x – 1 = 5
6 – 1 = 5
5 = 5
∴ LHS = RHS (verified)
(d) x + 6 = 2
The given equation is x + 6 = 2
Subtract 6 from both the sides
x + 6 - 6 = 2 - 6
x = - 4
Substitute the value of x = -4 in the given equation,
x + 6 = 2
-4 + 6 = 2
2 = 2
∴ LHS = RHS (verified)
(e) y – 4 = -7
The given equation is y – 4 = -7
Add 4 to both the sides
y - 4 + 4 = - 7 + 4
y - 4 + 4 = - 7 + 4
y = -3
substitute the value of y = -3 in the given equation
y – 4 = -7
-3 – 4 = -7
-7 = -7
∴ LHS = RHS (verified)
(f) y – 4 = 4
The given equation is y – 4 = 4
Add 4 to both the sides
y - 4 + 4 = 4 + 4
y = 8
substitute the value of y = 8 in the given equation
y – 4 = 4
8 – 4 = 4
4 = 4
∴ LHS = RHS (verified)
(g) y + 4 = 4
The given equation is y + 4 = 4
subtract 4 from both sides
= y - 4 + 4 = 4 - 4
y = 0
substitute the value of y = 0 in the given equation.
y + 4 = 4
0 + 4 = 4
4 = 4
∴ LHS = RHS (verified)
(h) y + 4 = -4
The given equation is y + 4 = -4
subtract 4 from both the sides
y = -8 (verified)
substitute the value of y = -8 in the given equation
y + 4 = -4
-8 + 4 = -4
-4 = -4
∴ LHS = RHS (verified)