(a) 3l = 42
The given equation is 3l = 42
Divide by 3 both the sides
\(\frac{3I}{3} = \frac{42}{3}\)
= I = 14
Substitute the value of l = 14 in the given equation
3l = 42
3(14) = 42
42 = 42
∴ LHS = RHS (verified)
(b) \(\frac{b}{2}\) = 6
The given equation is \(\frac{b}{2}\) = 6
Multiplied by 2 both the sides b
substitute the value of b = 12 in the given equation
∴ LHS = RHS (verified)
(c) \(\frac{p}{7}\) = 4
The given equation is \(\frac{p}{7}\) = 4
Multiplied by 7 to both the sides
4 = 4
∴ LHS = RHS (verified)
(d) 4x = 25
The given equation is 4 x = 25
Divide both sides by 4
substitue the value of x = \(\frac{25}{4}\) in the given equation
4x = 25
4 x \(\frac{25}{4}\) = 25
∴ LHS = RHS (verified)
(e) 8y = 36
The given equation is 8y = 36
Divide both sides by 8
Substitute the equation by y = \(\frac{9}{2}\) in the given equation
8y = 36
8 x \(\frac{9}{2}\) = 36
36 = 36
∴ LHS = RHS
(f) \(\frac{z}{3} = \frac{5}{4}\)
Substitute the equation by z = \(\frac{15}{4}\) in the given equation
∴ LHS = RHS (verified)
(g) \(\frac{a}{5} = \frac{7}{15}\)
Substitute the value of a = \(\frac{7}{3}\) in the given equation
∴ LHS = RHS (verified)
(h) 20t = -10
The given equation is 20 t = -10
Divide by 20 to both sides
LHS = RHS (verified)
