(a) 10p = 100
The given equation is 10p = 100
Divide by 10 both the sides
Substitute the value of p in the given equation
10p = 100
10 x 10 = 100
100 = 100
∴ LHS = RHS (verified)
(b) 10p + 10 = 100
The given equation is 10p + 10 = 100
subtract 10 from both the sides
Substitute the value of p = 9 in the given equation
10p + 10 = 100
10 × 9 + 10 = 100
90 + 10 = 100
100 = 100
LHS = RHS (verified)
(c) \(\frac{p}{4}\) = 5
5 = 5
∴ LHS = RHS (verified)
(d) \(\frac{-p}{3}\) = 5
The given equation is \(\frac{-p}{3}\) = 5
The equation is multiplied by -3 both the sides
Substitute the value of p = -15 in the given equation
∴ LHS = RHS (verified)
(e) \(\frac{3p}{4} = 6\)
Substitute the value p = 8 in the given equation
