(a) 3s = -9
The given equation is 3s = -9
Divide the equation by 3 both the sides
Substitute the value of s = -3 in the given equation
3s = -9
3(-3)=-9
-9 = -9
∴ LHS = RHS (verified)
(b) 3s + 12 = 0
The given equation is 3s + 12 = 0
subtract 12 from both the sides
3s + 12 - 12 = 0 - 12
3s = - 12
Divide by 3 both the sides
Substitute the value of s = -4 in the given equation
3s = 12 = 0
3(-4) = 12 = 0
-12 + 12 = 0
0 = 0
∴ LHS = RHS
(c) 3s = 0
The given equation is 3s = 0
Divide by 3 both the sides
\(\frac{3s}{3} = \frac{0}{3}\)
s = 0
Substitute the value of s = 0 in the given equation
3s = 0
3(0) = 0
0 = 0
∴ LHS = RHS (verified)
(d) 2q = 6
The given equation is 2q = 6
Divide the equation by 2 both the sides
\(\frac{2q}{2} = \frac{6}{2}\)
q = 3
substitute the value of q = 3 in the given equation
2q = 6
2(3) = 6 6 = 6
∴ LHS = RHS (verified)
(e) 2q – 6 = 0
The given equation is 2q – 6 = 0
Add 6 to both the sides
Substitute the value of q = 3 in the given equation
2q – 6 = 0
2(3) – 6 = 0
6 – 6 = 0
0 = 0
LHS = RHS (verified)
(f) 2q + 6 = 0
The given equation is 2q + 6 = 0
Subtract 6 from both the sides
2q - 6 + 6 = 0 - 6
2q = - 6
Divide by 2 both the sides by 2
Substitute the value of q = -3 in the given equation
2q + 6 = 0
2(-3) + 6 = 0
-6 + 6 = 0
0 = 0
∴ LHS = RHS (verified)
(g) 2q + 6 = 12
The given equation is 2q + 6 = 12
Subtract 6 from both the sides
2q - 6 + 6 = 12 - 6
2q = 6
Divide by 2 both the sides
