(a) 4 = 5 (p – 2)
The given equation is 4 = 5 (p – 2)
5(p – 2) = 4 [LHS and RHS are inter-changed the equation remains the same]
Divide by 5 both sides
Substituting the value of p = 
in the given equation
(b) -4 = 5 (p – 2)
The given equation is – 4 = 5 (p – 2)
[LHS & RHS are interchanged the equation remains same]
5 (p – 2) = -4
Divide by 5 both the sides
Substitute the value of P = 6/5 in the given equation
5(p – 2) = -4
∴ LHS = RHS (verified)
(c) 16 = 4 + 3 (t + 2)
The given equation is 16 = 4 + 3 (t + 2)
4 + 3 (t + 2) = 16 [LHS and RHS are interchanged the equation remains the same.] 4 + 3t + 6 = 16
3t + 10 = 16
3t = 16 – 10 [ transposing + 10 from LHS to RHS, it becomes -10]
3t = 6
t = 6/3 = 2 ∴ t = 2
Substitute the value of t = 2 in the given equation
16 = 4 + 3 (t +2)
16 = 4 + 3t + 6
16 = 10 + 3(2)
16 = 10 + 6
16 = 16
∴ LHS = RHS (verified)
(d) 4 + 5 (p – 1) = 34
The given equation is 4 + 5 (p – 1) = 34
Transpose 4 from LHS to RHS
5(p – 1) = 34 – 4 (on transposing 4 becomes -4)
5(p – 1) = 30
Divide by 5 both sides
p – 1 = 6
Transposing -1 from LHS to RHS p = 6 + 1 [on transposing -1 becomes 1]
p = 7
Substitute the value of p = 7 in the given equation
4 + 5(p – 1) = 34
4 + 5p – 5 = 34
4 + 5 (7) – 5 = 34
4 + 35 – 5 = 34
34 = 34
∴ LHS = RHS (verified)
(e) 0 = 16 + 4(m – 6)
The given equation is 0 = 16 + 4 (m – 6)
16 + 4 (m – 6) = 0 [ LHS ami RHS are interchanged the equation remains the same] Transpose 16 from LHS to RHS .
4(m – 6) = 0 – 16 [on transposing 16 becomes -16]
4(m – 6) = -16
Divide by 4 both sides
m – 6 = – 4
Transpose – 6 from LHS to RHS
m = – 4 + 6 [on transposing – 6 becomes + 6]
m = 2
Substitute the value m = 2 in the given equation
16 + 4(m – 6) = 0
16 + 4(2 – 6) = 0
16 + 4(-4) = 0
16 – 16 = 0
0 = 0
∴ LHS = RHS (verified)
