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in Triangles by (65.5k points)

Find the value of the unkown interior angle x in the following figures:

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(i) ∠x + 50° = 115°

∵ The exterior angle of a triangle is equal to the

sum of its two interior opposite angles.

∵ ∠x = 115° – 50° = 65°

(ii) ∠x + 70° = 100°

(∵ The exterior angle of a triangle is equal to the sum of its two interior opposite angles)

∴ ∠x = 100° – 70°= 30°

(iii) ∠x + 90° = 125°

∵ The exterior angle of a triangle is equal to the sum of its two interior opposite angles.

∴ ∠x = 125° – 90° = 35°

(iv) ∠x + 60° = 120°

∵ The exterior angle of a triangle is equal to the sum of its two interior opposite angles.

∠x = 120° – 60° = 6o°

(v) ∠x + 30° = 80°

∵ The exterior angle of a triangle is equal to the sum of its two interior opposite angles.

∵ ∠x = 80° – 30° = 50°

(vi) ∠x + 35° = 75°

∵ The exterior angle of a triangle is equal to the sum of its two interior opposite angles.

∴ ∠x = 75° – 35° = 40°

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