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0 votes
1.5k views
in Electrochemistry by (80 points)
Given the data at 25°C Ag + I-–> AgI + e, E° =0.152, Ag–> Ag^+ + e, E°=-800. What is the value of log KSP for AgI?

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1 Answer

+1 vote
by (5.0k points)

The correct answer is -16.13

(i) Ag →Ag++ e− E= −0.800V

(ii) Ag + I− → Agl + e−  E∘ =0.152V

(I) - (II) we have AgI → Ag+ + I

E=−0.952V

by (80 points)
Thank you
by (5.0k points)
+1
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