Question

For a PN junction the average value of a potential well is 0.1 V and the electric field 10⁵ V/m is present at junction region. What will be the width of depletion layer for this junction?

Answer 1

Average value of potential well V_B = 0.1 V
Electric field at junction region E = 10⁵ V/m
∴ Width of depletion layer for this junction
d = \(\frac{V_{B}}{E}\) {∵ E = \(\frac{V}{d}\)}
or d = \(\frac{0.1}{10^{5}}\) = 10^-6 m