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Construct ∆ DEF such that DE = 5 cm, DF = 3 cm and ∠EDF = 90°.

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Construct ∆ DEF such that DE = 5 cm, DF = 3 cm and ∠EDF = 90°.

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Steps of Construction

1. Draw a line segment DE of length 5 cm. At D draw DM making 90° with DE.

2. With ‘D’ as centre, draw an arc of radius 3 cm, It cuts DM at the point F.

3. Join FE. The required triangle is obtained. That is ∆ DEF.

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