Question

0.2L aqueous solution of protein contains 1.26 g protein. The osmotic pressure of this solution is 2. 57 x 10^-3 bar at 300 K. Calculate the molecular mass of protein.

Answer 1

Given that,
Volume ‘V’ = 0.2 L
Mass of solute ‘W_B‘ = 1. 26 g
Temperature ‘T’ = 300 K,
Osmotic pressure ‘π’ = 2.57 x 10^-3 bar
Gas constant ‘R’ = 0. 0821 L bar mol^-1 K^-1

= 60377.04 g/mol
Molecular mass of protein = 60377.04 g/mol