Question

Calculate the temperature at which the solution of 54g glucose present in 250g water will be freezed.
(K_f =1.86 K kg mol^-1)

Answer 1

Given that:
Weight of solute (W_B) = 54g
Molecular weight of solute (M_B) = 180 g mol
Weight of solvent (W_A) = 250g
K_f = 1.86 K kg mol^-1
Depression in freezing point ∆T_f

Depression in freezing point = 2.23 K
Freezing point of solution = ?
Freezing point of water = 273.15 K
(∆T_f) = Freezing point of water – Freezing point of solution
Freezing point of solution = 273.15 – 2.23= 270.92