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Consider the reaction

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in Electrochemistry by (57.3k points)

Consider the reaction
Cr2O72- + 14H+ + 6e– →  2Cr3+ + 7H2O
What is the quantity of electricity in coulombs needed to reduce 1 mol of Cr2O72-

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According to equation for the reduction of one mole of Cr2O72- , 6 mole of electrons are needed. Hence the amount of electricity require = 6F
= 6 x 96500 C = 579000 C

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