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Xand Y are two volatile liquids with molar weight 10g mol-1 and 40g mol-1, respectively.

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The correct answer is increased collision frequency of X with the inert gas as compared to that of Y with the inert gas

  • X is a lighter gas than Y, hence X  has greater molecular speed. 
  • Due to the greater molecular speed of X, it will have a smaller mean free path and greater collision frequency with the inert gas molecules. 
  • As a result, X will take more time to travel a given distance along a straight line.
  • Hence X and Y will meet at a distance smaller than one calculated from Graham's law
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jee adv physics doubt
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