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A bulb rated 60W at 220V is connected across a household supply of alternating voltage of 220V.

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A bulb rated 60W at 220V is connected across a household supply of alternating voltage of 220V. Calculate the maximum instantaneous current through the filament.

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1 Answer

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by (150k points)

P = 60W V = 220 V = E

R = V2/P = (220 x 220) = 806.67

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