Sarthaks APP
0 votes
1.8k views
in Chemistry by (2.8k points)

1 Answer

0 votes
by (15.1k points)
selected by
 
Best answer

Molecular mass of Ozone(O3)= 3X16=48gmol-1

Now, At STP conditions, all gases contain volume=22.4L

Thus at STP, 48g O3----- 22.4L

1g O3----- 22.4 / 48 L

thus 1g O3------ 22.4 X 1 / 48 = 22.4 / 48 L = 0.4667 L

by (2.8k points)
The answer is not in any option. You might want to recheck it.
by (15.1k points)
ohh, Now I have edited my answer. There was a silly mistake. Now its right
Sarthaks APP

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...