According to Ellingham diagram:
1. Temperature 1073K respresents intersection point.
2. Reduction of haematite below 1073 K is done by carbon monoxide. Hence
∆G°(Fe → Fe2O3) > ∆G°(CO → CO2)
Reaction completes in following way:
Fe2O2(s) + 3C(g) \(\overset{< \,1073k}{\longrightarrow}\) 2Fe(s) + 3CO2(g)
3. Reduction of haematite above 1073 K is done by coke (or carbon). Hence
∆G°(Fe → Fe2O3) > ∆G° (C → CO)
In this way reduction is as follows:
Fe2O3(s) + C(s) \(\overset{Temp\,>\,1073k}{\longrightarrow}\) 2Fe(s) + 3CO(g)
