**Correct Answer is 95.2%**

Therefore, 143.5 g of AgCl would be precipitated by 108 g of Ag.

or, 14.35 g of silver chloride would be precipitated by 10.8 g of silver because 11.34 g of silver coin contain 10.8 g of pure silver.

Therefore, 100 g of silver coin contain

10.8/11.34× 100

=95.2 %

**So, coin contains 95.2% silver.**