Given: The lengths of three pieces of timber are 42 m, 49 m and 63 m respectively. We have to divide the timber into equal length of planks.
Greatest possible length of each plank = HCF (42, 49, 63)
The prime factorization of 42, 49 and 63 are:
42 = 2 x 3 x 7
49 = 7 x 7
63 = 3 x 3 x 7
HCF (42, 49, 63 ) = 7
The greatest possible length of each plank is 7 m.
Again, The number of planks can be formed = 22
