Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.5k views
in Number System by (58.8k points)

Find the least number of square tiles required to pave the ceiling of a room 15 m 17 cm long and 9 m 2 cm broad.

1 Answer

+1 vote
by (44.3k points)
selected by
 
Best answer

Length of a tile = 15m 17m = 1517 cm

Breadth of a tile = 9m 2m = 902 cm

Required number of tiles =( Area of ceiling)/ (Area of one tile ) …..(1)

Side of each tile = HCF (1517 and 902)

1517 = 37 x 41

902 = 22 x 41

HCF = 41

Area of one tile = (side)2 = 41 x 41

Equation (1) implies

Required number of tiles = (1517 x 902)/41×41 = 814

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...