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in Polynomials by (58.8k points)

Find the zeros of the quadratic polynomials x2 - 2x - 8 and verify the relationship between the zeros and the coefficients.

1 Answer

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Best answer

Let f(x) = x2 ˗ 2x ˗ 8

= x2 ˗ 4x + 2x ˗ 8

= x(x ˗ 4) + 2(x ˗ 4)

= (x ˗ 4) (x + 2)

To find the zeroes, set f(x) = 0, then

either (x ˗ 4) = 0 or (x+2) = 0

x = 4 or x = -2

Again,

Sum of zeroes = (4 – 2) = 2 = 2/1

= -b/a

= (-Coefficient of x)/(Cofficient of x2)

Product of zeroes = (4) (-2) = -8/1

= c/a

= Constant term / Coefficient of x2

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