Let f(x) = 4x2 ˗ 4x + 1
= (2x2) – 2(2x)(1) + (1)^2
= (2x – 1)2
To find the zeroes, set f(x) = 0
(2x – 1)2 = 0
x = 1/2 or x = 1/2
Again,
Sum of zeroes = 1/2+1/2=1=1/1
= -b/a
= (-Coefficient of x) / (Cofficient of x2)
Product of zeroes = 1/2 x 1/2=1/4
= c/a
= Constant term / Coefficient of x2