Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
64.1k views
in Polynomials by (58.8k points)

Find the zeros of the quadratic polynomials 4x2 – 4x + 1 and verify the relationship between the zeros and the coefficients.

1 Answer

+1 vote
by (44.3k points)
selected by
 
Best answer

Let f(x) = 4x2 ˗ 4x + 1

= (2x2) – 2(2x)(1) + (1)^2

= (2x – 1)2

To find the zeroes, set f(x) = 0

(2x – 1)2 = 0

x = 1/2 or x = 1/2

Again,

Sum of zeroes = 1/2+1/2=1=1/1

= -b/a

= (-Coefficient of x) / (Cofficient of x2)

Product of zeroes = 1/2 x 1/2=1/4

= c/a

= Constant term / Coefficient of x2

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...