Let ∝ = 2 and β = -6
Sum of the zeroes = (∝ + β) = 2 – 6 = -4
Product of the zeroes, = 2(-6) = -12
Required quadratic polynomial is
x2 – (∝+β)x + ∝β
= x2 – (-4)x – 12
= x2 + 4x – 12
And,
Sum of the zeroes = – 4 = -4/1 = (-Coefficient of x)/(Cofficient of x2)
Product of zeroes = -12 = -12/1 = Constant term / Coefficient of x2