Given : Sum of zeroes = (∝ + β) = 8
Product of the zeroes = = 12
Required quadratic polynomial is
x2 – (∝+β)x + ∝β
= x2 – (8)x + 12
Now, find the zeroes of the above polynomial.
Let f(x) = x2 – (8)x + 12
= x2 – 6x – 2x + 12
= (x -6)(x – 2)
Substitute f(x) = 0.
either (x -6) = 0 or (x – 2) = 0
x = 6 or x = 2
2 and 6 are the zeroes of the polynomial.