Given: (x + a) is a factor of polynomial 2x2 + 2ax + 5x + 10.
So, we have
x + a = 0
or x = –a , will satisfy the given polynomial.
Therefore, we will have
2 (–a)2 + 2a(–a) + 5(–a) + 10 = 0
2a2 –2a2 – 5a + 10 = 0
– 5a = – 10
a = 2
The value of a is 2.