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If (x + a) is a factor of (2x^2 + 2ax + 5x + 10), find the value of a.

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If (x + a) is a factor of (2x2 + 2ax + 5x + 10), find the value of a.

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Given: (x + a) is a factor of 2x2 + (2a + 5) x + 10.

Which shows that one of the zeros of the given polynomial is x + a = 0, i.e. –a.

Now, x = -a satisfy the given polynomial.

2 (-a)2 + (2a + 5)(-a) + 10 = 0

2a2 – 2a2 – 5a + 10 = 0

5a = 10

a = 2

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