f(x) = 4√3x2 + 5x ‒ 2√3
To find the zeros of the quadratic polynomial, put f(x) = 0
4√3x2 + 5x ‒ 2√3 = 0
4√3 x2 + 8x – 3x – 2√3 = 0
4x (√3 x + 2) – √3 (√3 x + 2) = 0
(4x – √3) (√3 x + 2) = 0
Either (√3 x + 2) = 0 or (4x – √3) = 0
x = -2/√3 or x = √3/4