Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
2.4k views
in Chemical Thermodynamics by (75 points)
In a fuel cell methanol is used as a fuel and oxygen is used as an oxidising the reaction is

 ch3oh(l) + 3/2 O2 (g) ———> CO2(g) + 2 H2O(l)

At 298 K standard Gibbs energy of formation of methanol, H2O and CO2 are - 166.2, - 237.2 and -394.4 KJmole-1 respectively. If standard enthalpy of combustion of methanol is - 76 kilo joule per mole efficiency of fuel cell will be?

Please log in or register to answer this question.

2 Answers

+1 vote
by (5.0k points)

The reaction for the combustion of methanol is:

The efficiency of conversion of Gibbs free energy into useful work.

or efficiency =−702.6−/726 ×100

= 97%

by (75 points)
Thank you sir
by (5.0k points)
Welcome
+1 vote
by (1.7k points)

The reaction for combustion of methanol is:
CH3​OH(l)+23​O2​(g)⟶21​CO2​(g)+2H2​O(l)


ΔGreactiono​=[ΔGfo​CO2​(g)+2ΔGfo​H2​O(l)]−[ΔGfo​CH3​OH(l)+23​ΔGfo​O2​(g)]


[−394.36+2(−237.13)]−[−166.27+0]


=−702.35kJmol−1


The efficiency of conversion of Gibbs free energy into useful work


=ΔHreactiono​ΔGreactiono​×100​=−726−702.35×100​=96.7

by (75 points)
Thank you

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...