Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
20.1k views
in Linear Equations by (44.3k points)

Find the value of k for the system of equations has a unique solution:

2x + 3y – 5 = 0, kx – 6y – 8 = 0.

1 Answer

+1 vote
by (58.8k points)
selected by
 
Best answer

2x + 3y – 5 = 0 ………….(1)

kx – 6y – 8 = 0 ………..(2)

a1 = 2, b1 = 3, c1 = – 5

a2 = k, b2 = – 6, c2 = – 8

System has a unique solution.

Now, Find the value of k:

2/k ≠ 3/-6

k ≠ -4

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...