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An element A burns with golden flame in the air. It reacts with another element B, atomic number 17

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An element A burns with golden flame in the air. It reacts with another element B, atomic number 17 to give a product C. An aqueous solution of product C on electrolysis gives a compound D and liberates hydrogen. Identify A, B, C and D. Also write down the equations for the reactions involved.

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Element A is 17 Sodium because it will burn with golden flame in air. 

Element B is Chlorine for its atomic number is 17. 

Product C is Sodium Chloride 

2Na + Cl2 → 2NaCl

Product D is Sodium hydroxide 

2NaCl + 2H2O → 2NaOH + Cl2 + H2

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