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in Basic Concepts of Chemistry by (48.1k points)

Calcium carbonate reacts with aqueous HCl to give CaCl2 and CO2 according to the reaction, CaCO3 (s) + 2HCl (aq) → CaCl2 (aq) + CO2 (g) + H2O (l). What mass of CaCO3 is required to react completely with 25 mL of 0.75 M HCl ?

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1000 mL of.0.75 M HCl have 0.75 mol of HCl = 0.75 x 36.5 g = 24.375 g
(Molar mass of HCl is 36.5)
Mass of HCl in 25 mL of 0.75 M
HCl = 24.375/1000 x 25 g = 0.6844 g
According to the given chemical equation,
CaCO3 (s) + 2HCl(ag) →CaCl2 (aq) + CO2(g) + H2O(Z)
2 mol of HCl i.e. 73 g HCl react completely with 1 mol of CaCO3g i.e. 100 g
.’. 0.6844 g HCl reacts completely with CaCO3 = 100/73 x 0.6844 g = 0.938 g

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