(i) Energy (E) of a photon is given by the expression,
E = hv
Where, h = Planck’s constant = 6.626 × 10-34 Js
v = frequency of light = 3 × 1015 Hz (Given) Substituting the values we get,
E = (6.626 × 10-34) × (3 × 1015)
E = 1.988 × 10-18 J
(ii) Energy (E) of a photon having wavelength (λ) is given by the expression,
Where, E = \(\frac{h c}{\lambda}\)
h = Planck’s constant = 6.626 × 10-34 Js
c = velocity of light in vacuum = 3 × 108 m/sec
X = wavelength = 0.50 A or 0.50 × 10-10 m
Substituting values in expression we get,
= 6.626 × 10-34 × 3 × 108/ 0.50 × 10-10
= 3.98 × 10-15 J