Question

Calculate the wavelength of electron if it is moving with a velocity of 2.05 × 10⁷ ms^-1.

Answer 1

According to de Broglie’s equation,
λ = h/mv
Where, λ = wavelength of moving particle
m = mass of particle (9.109 × 10^-31 Kg)
v = velocity of particle (2.05 × 10⁷ ms^-1)
h = Planck’s constant (6.626 × 10^-34)Js
Substituting the values in the expression of A:
X = (6626 × 10^-34 Js) / (9.109 × 10^-31)(2.05 × 10⁷ ms^-1)
= 3.54 × 10^-11 m
Hence, the wavelength of the electron is 3.54 × 10^-11 m.