Question

If two moles of an ideal gas at 546 K have volume 44.8 L, then what will be its pressure ?

Answer 1

We know that, PV = nRT … (i)
Where, P = Pressure of gas
V = Volume of gas = 44.8L
n = Number of moles of gas = 2
R = Gas constant = 0.082 L atm K^-1 mol^-1
T = Temperature of gas = 546 K
From equation (i) we have,
P = n RT/V
= 2 × 0.082 × 546/44.8
= 1.998 atm.