Let d be the common difference.
Given:
first term = a = -4
last term = l = 29
Sum of all the terms = Sn = 150
Sn = n/2[a + l]
150 = n/2[-4 + 29]
n = 12
There are 12 terms in total.
Therefore, 29 is the 12th term of the AP.
Now, 29 = -4 + (12 – 1)d
29 = -4 + 11d
d = 3
The common difference is 3.