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What will be the pressure of the gaseous mixture when 0.5 L of H2 at 0.8 bar and 2.0 L of dioxygen at 0.7 bar are introduced in 1 L vessel at 27°C?

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The equation PV = nRT for the two gases can be given as:
For H2
0. 8 × 0.5 = nH2 × RT or nH2 = 0.8 × 0.5/RT = 0.4/RT
And, for O2
0. 7 × 2.0 = nO2. RT or nO2 = 0.7 × 2/RT = 1.4/RT When introduced in 1 L vessel, then
P × 1 = (nO2 + nH2) RT
Putting the values, we get
P = 0.4 + 1.4 = 1.8 bar
Hence, the total pressure of the gaseous mixture in the vessel is 1.8 bar.

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