Question

What will be the pressure of the gaseous mixture when 0.5 L of H₂ at 0.8 bar and 2.0 L of dioxygen at 0.7 bar are introduced in 1 L vessel at 27°C?

Answer 1

The equation PV = nRT for the two gases can be given as:
For H₂
0. 8 × 0.5 = nH₂ × RT or nH₂ = 0.8 × 0.5/RT = 0.4/RT
And, for O₂
0. 7 × 2.0 = n_O2. RT or n_O2 = 0.7 × 2/RT = 1.4/RT When introduced in 1 L vessel, then
P × 1 = (n_O2 + n_H2) RT
Putting the values, we get
P = 0.4 + 1.4 = 1.8 bar
Hence, the total pressure of the gaseous mixture in the vessel is 1.8 bar.