For the given reaction,
When we substitute the values of ∆Hθ and ∆Sθ in the expression of ∆Gθ, then according to Gibbs’ Helmholtz equation;
∆Gθ = ∆Hθ – T∆Sθ
= -12.98 kJ – (298 K) (-44.1 J K-1)
=-12.98 kJ - (-13.14 kJ)
∆Gθ = 0.16 kJ
Since ∆Gθ for the reaction is positive, the reaction will not occur spontaneously.