Question

A swimming pool contains 1 x 10⁵ L of water. How much energy in Joule is required to raise the temperature of water from 20⁰c to 25⁰c ? The specific heat capacity of water is 4.184 J/⁰C g

Answer 1

Volume of water= 10⁵ L = 10⁸ mL

Mass of water= Vx d ... d= 1g/mL

=10⁸x1=10⁸ g

Specific heat of water, Cs =4.184 J/⁰C

Heat absorbed by the water to raise the temperature may be calculated as,

q = mC_s ΔT

q = 10⁸ x 4.184x 5=2.092 x 10⁹J