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If the points P (x, y) is equidistant from the points A (5, 1) and B (-1, 5), prove that 3x = 2y.

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Since P (x, y) is equidistant from A (5, 1) and B (-1, 5), then

PA = PB

or PA2 = PB2

(5 – x)2 + (1 – y)2 = (– 1 – x)2 + (5 – y)2

(25 + x2 – 10x) + (1 + y2 – 2y) = (1 + x2 + 2x + 25 + y2 – 10y)

26 + x2 – 10x + y2 – 2y = (26 + x2 + 2x + y2 – 10y)

12x = 8y

3x = 2y

Hence proved.

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