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in Oxidation-Reduction Reactions by (49.3k points)

Draw the diagram of Galvanic cell which represents the following reaction :
Zn + 2Ag+ ➝  Zn2++ 2Ag
Answer the following question :
(a) Give equation for the reaction taking place at each electrode.
(b) In which direction electrons in external circuit flows ?
(c) Identify anode and cathode.
(d) If E° Zn2+/Zn = 0.76 an E° Ag+/ Ag = +0. 80 volt, then whether E° = 1.56 volt ?

1 Answer

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by (48.1k points)
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Best answer

(a) Reaction taking place at anode :
Zn → Zn2+ + 2e
Reaction taking place at cathode-
2Ag+ + 2e → 2Ag

(b) Electrons in external circuit flow anode to cathode.

(c) Zn in anode and Ag in cathode.

(d) E°cell = E°cathode – E° anode
= E° Ag+ / Ag = E° Zn2+ / Zn
= 0. 80 - (- 0.76)
= 0.80 + 0.76 = 1.56 volt

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