(a) Reaction taking place at anode :
Zn → Zn2+ + 2e–
Reaction taking place at cathode-
2Ag+ + 2e– → 2Ag
(b) Electrons in external circuit flow anode to cathode.
(c) Zn in anode and Ag in cathode.
(d) E°cell = E°cathode – E° anode
= E° Ag+ / Ag = E° Zn2+ / Zn
= 0. 80 - (- 0.76)
= 0.80 + 0.76 = 1.56 volt