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If the point P (k – 1, 2) is equidistant from the points A (3, k) and B (k, 5), find the values of k.

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If the point P (k – 1, 2) is equidistant from the points A (3, k) and B (k, 5), find the values of k.

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Point P (k – 1, 2) is equidistant from the points A (3, k) and B (k, 5).

PA = PB or PA2 = PB2

k(k-1)-5(k-1) = 0

(k-5)(k-1) = 0

k = 1 or k = 5

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