Length of wire = AC = 24 m
Height of the pole = AB = 18 m
Let Distance between the base of the pole and other end of the wire = BC = x m
In right ∆ABC,
By Pythagoras Theorem:
AC2 = AB2 + BC2
(24)2 = (18)2 + x2
576 = 324 + x2
x2 = 576 – 324 = 252
or x = 15.8 m
BC is 15.8 m.