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Prove that cosec (65 °+ θ) sec (25° − θ) − tan (55° − θ) + cot (35° + θ) = 0.

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Prove that cosec (65 °+ θ) sec (25° − θ) − tan (55° − θ) + cot (35° + θ) = 0.

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L.H.S.

= cosec (65° + θ) - sec (25° - θ) - tan (55° - θ) + cot (35° + θ)

= cosec (65° + θ) - sec (90° – (65° + θ)) - tan (90° – (35° + θ)) + cot (35° + θ)

= cosec (65° + θ) - cosec (65° + θ)) - cot (35° + θ) + cot (35° + θ)

= 0

= R.H.S.

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